The macro will work for any number of items in the A column, within Excel limits. If (UBound(vresult) = UBound(unique)) ThenĬall PermutationsNPR(vElements, p, vresult, lRow, iIndex + 1)įunction UniqueArray(todoarray As Variant) As Variant Sub PermutationsNPR(vElements As Variant, p As Long, vresult As Variant, lRow As Long, iIndex As Integer) VElements = Application.Transpose(Range("A1", Range("A1").End(xlDown)))Ĭall PermutationsNPR(vElements, i, vresult, lRow, 1) The following VBA script created for me this spreadsheet:ĭim vElements As Variant, vresult As Variant It doesn't give me all possible combinations permutations, it just changes what I typed in vertically down a column, and outputs the results horizontally. In column B the VBA gives me (in a single cell): one,two,three In column A, if I type (one word per row): One That doesnt work for me because the matrices are adjacency matrices (representing graphs), and I need to do the permutations which will give me a. numpy.shuffle and numpy.permutation seem to permute only the rows of the matrix (not the columns at the same time). I have given this a try but it does not seem to work. But, I would like to know if there is something more efficient that does this. I would like to be able to type in any number of input values and the input values will be any word, phrase, number, letters, or a combination permutation of all of those. Here is what it should look like if 3 values are given:ĭoes anyone know how to do this in Excel? The output generated should be something like this One The word 'permutation' also refers to the act or process of changing the linear order of an ordered set. 172), is a pseudotensor which is antisymmetric under the interchange of any two slots. In mathematics, a permutation of a set is, loosely speaking, an arrangement of its members into a sequence or linear order, or if the set is already ordered, a rearrangement of its elements. How do I go about creating a formula which takes any number of given input values, and then generates an output value with all possible combinations permutations based on the input values given.įor example, if the input values where as following One The permutation tensor, also called the Levi-Civita tensor or isotropic tensor of rank 3 (Goldstein 1980, p. Therefore, the suggested duplicate does not answer my question. The suggested duplicate always shows column A at the left most position of the output, column b in the middle of the output and column c at the left of the output. is that permute is to change the order of something while permutate is to carry out a permutation. The suggested duplicate always provides 3 inputs per variation.įurthermore, my question also asks for variations to show all possible orders of the inputs too. As verbs the difference between permute and permutate. Permutations are specific selections of elements within a set where the order in which the elements are arranged is important, while combinations involve the selection of elements without regard for order. The suggested duplicate does not show all possible variations based on the number of options, so an input of 3 can have a variation of 1, 2, and 3 of the inputs. Permutations and combinations are part of a branch of mathematics called combinatorics, which involves studying finite, discrete structures. Try this formula out in Excel.Please note my question is different from the suggested duplicate. The same concept can be applied to additional columns simply modify the counter to account for additional permutations.įor more than two lists, you need to take a different approach with your counter. Using the INDEX function and MOD function, we can loop through list B and print its values until there are no permutations left to print. ![]() Now that we have the number of possibilities for list A, we can join list B. ![]() If you need a text separator for the permutations between the lists, you can use the & symbol. This will give us an output of every value in list A multiplied by the number of values in list B. Here we are essentially saying, look at list A, loop through it according to list B, and if we reach the end of list B, go on to the next value in list A, restart. To do so, we will use the INDEX formula combined with the INT formula. ![]() ![]() If the index of the current row minus the first row plus 1 is greater than the count of possible permutations, then we can leave that cell blank, otherwise, we want to return one of the permutations. Start with an if statement to bound your data. You can create permutations by implementing a counter that cycles through your lists until it reaches the end.įor example let's say your lists are in columns A and B, and you want an array of possible permutations in column C.
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